Given numbers – 1000000
Number of digits = 7
The numbers have to be greater than 1000000, so they can begin either with 1, 2 or 4.
When 1 is fixed at the extreme left position, the remaining digits to be rearranged will be 0, 2, 2, 2, 4, 4, in which there are 3, 2s and 2, 4s.
Thus, the number of numbers beginning with 1 = 6!/(3! 2!) = (6 × 5 × 4 × 3!)/(3! × 2)
= 60
The total numbers begin with 2 = 6!/(2! 2!) = 720/4 = 180
Similarly, the total numbers beginning with 4 = 6!/3! = 720/6 = 120
Therefore, the required number of numbers = 60 + 180 + 120 = 360.