f : ( 0 , 2 ) → R f ( x ) = x 2 + 2 x g ( x ) g ( x ) = min { f ( t ) } , 0 < t ≤ x and 0 < x ≤ 1 3 2 + x , 1 < x < 2 g x = 1 g x ∈ ( 0 , 2 ) g x = 1 g x ∈ ( 0 , 2 ) Spread the love